命题" $\exists x_0\in (0,+\infty ),\ln x_0\ne x_0-1$"的否定是（  ）

$\exists x_0\in (0,+\infty ),\ln x_0\ne x_0-1$ $\exists x_0\notin (0,+\infty ),\ln x_0=x_0-1$ $\forall x\in (0,+\infty ),\ln x\ne x-1$ $\forall x\notin (0,+\infty ),\ln x=x-1$